(x^2-1)^2-10(x^2-1)+16=0

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Solution for (x^2-1)^2-10(x^2-1)+16=0 equation: 



(x^2-1)^2-10(x^2-1)+16=0

We multiply parentheses

-10x^2+(x^2-1)^2+10+16=0

We add all the numbers together, and all the variables

-10x^2+(x^2-1)^2+26=0

We move all terms containing x to the left, all other terms to the right

-10x^2+(x^2-1)^2=-26

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